Javascript ตรวจสอบรูปแบบ URL

24 ก.พ. 2020 , 2,826 Views , หมวดหมู่ jQuery,JavaScript,Ajax โค๊ดดิ้ง , ป้ายกำกับ:Check URL Valid, javascript, validURL

Javascript Check URL Valid

function validURL(str) {
  var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol
    '((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name
    '((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address
    '(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path
    '(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string
    '(\\#[-a-z\\d_]*)?$','i'); // fragment locator
  return !!pattern.test(str);
}

function validURL(str) {

var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol

'((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name

'((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address

'(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path

'(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string

'(\\#[-a-z\\d_]*)?$','i'); // fragment locator

return !!pattern.test(str);

}

ตัวอย่าง

function validURL(str) {
  var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol
    '((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name
    '((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address
    '(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path
    '(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string
    '(\\#[-a-z\\d_]*)?$','i'); // fragment locator
  return !!pattern.test(str);
}
	
console.log(validURL('seenual.com'));

function validURL(str) {

var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol

'((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name

'((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address

'(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path

'(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string

'(\\#[-a-z\\d_]*)?$','i'); // fragment locator

return !!pattern.test(str);

}

console.log(validURL('seenual.com'));

ผลลัพธ์ : true

function validURL(str) {
  var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol
    '((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name
    '((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address
    '(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path
    '(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string
    '(\\#[-a-z\\d_]*)?$','i'); // fragment locator
  return !!pattern.test(str);
}
	
console.log(validURL('seenualcom'));

function validURL(str) {

var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol

'((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name

'((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address

'(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path

'(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string

'(\\#[-a-z\\d_]*)?$','i'); // fragment locator

return !!pattern.test(str);

}

console.log(validURL('seenualcom'));

ผลลัพธ์ : false

ดูเพิ่มเติม : https://stackoverflow.com/questions/5717093/check-if-a-javascript-string-is-a-url/49849482

ป้ายกำกับ:Check URL Valid, javascript, validURL

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